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Maximum Height. The maximum height, y max, can be found from the equation: v y 2 = v oy 2 + 2 a y (y - y o) y o = 0, and, when the projectile is at the maximum height, v y = 0. - read more

First resolve the vertical component of your equation with the formula: Fsinθ (In layman's terms, Force X Sine X anglethrown) This is your initial velocity. At maximum height, velocity is ALWAYS 0. So: Since: V^2 = U^2 + 2as Then: S=(V^2-U^2) / 2a Eg: If we threw a ball at 26ms with an angle of ... - read more

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