### Possible Answer

Best Answer: Required line (say ℓ) is perp to both ℓ₁ & ℓ₂ ∴ its direction is d = (2,-3,1) X (0,0,5) = (-15,-10,0) ≡ (3,2,0) ℓ lies in the plane defined by ℓ₁ and d. This plane has normal d X (2,-3,1) = (2,-3,-13) and includes point (-5,-1,1) Hence its equation is 2x−3y ... - read more

How to Find a Line Perpendicular to Another. ... add 2 to both sides of the equation, which results in y - 2 + 2 = (1/2)x + 2. This leaves y = (1/2)x + 2, which is the line written in its slope ... How to Find a Perpendicular Line. If a line intersects another line at a 90-degree ... - read more

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